area of the remaining portion of the square
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Side of square = 8cm
area of square = side×side = 8×8 = 64cm²
radius of a circle = 2.1cm
area of circle = πr²= 22/7×2.1×2.1 =13.86cm²
Theta = 90
radius = 1.4cm
area of quadrant = πr²theta/360
= 22/7×1.4×1.4×90/360=1.54
area of two quadrant = 2×1.54 = 3.08cm
Area of the remaining portion of the square = Area of square-(area of two quadrant+ area of circle)
SOLVE THIS YOU WILL GET YOUR ANSWER...
area of square = side×side = 8×8 = 64cm²
radius of a circle = 2.1cm
area of circle = πr²= 22/7×2.1×2.1 =13.86cm²
Theta = 90
radius = 1.4cm
area of quadrant = πr²theta/360
= 22/7×1.4×1.4×90/360=1.54
area of two quadrant = 2×1.54 = 3.08cm
Area of the remaining portion of the square = Area of square-(area of two quadrant+ area of circle)
SOLVE THIS YOU WILL GET YOUR ANSWER...
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