Area of the rhombus be 24 cm and one of it's diagonals be 4cm find the perimeter
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Area of rhombus =product of diagonals /2
24=product of diagonals /2
48/4=II Diagonal =12
By Pythagoras theorem
6²+2²=side²
36+4=side²
√40=side
2√10=side
Perimeter =4*2√10
Perimeter =8√10
24=product of diagonals /2
48/4=II Diagonal =12
By Pythagoras theorem
6²+2²=side²
36+4=side²
√40=side
2√10=side
Perimeter =4*2√10
Perimeter =8√10
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