Question

area of the rhombus is 96 sqcm one of the diagonals is 12 cm find the length of other diagonals​

Answer 1

Answer:

the other diagonal is 16 cm

Step-by-step explanation:

let the other diagonal be X cm

so 1/2(12*X)=96

=6x=96

X=96/6

so X = 16 cm

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Answer 2

$\huge\mathfrak\orange{Ans}\purple{wer}\red {♡♡♡}$

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Formula:

$\frac{1}{2} \times product \: of \: diagonals$

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Let the second diagonal be D²:

$96 = \frac{1}{2} \times \frac{1}{2} \times {D}^{2}$

⟹ $6 {D}^{2} = 96$

⟹ ${D}^{2} = \frac{96}{6}$

$= 16cm$

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$\large{\underline{\sf{\blue{Side\:of\:rhombus\:}}}}$

$\sqrt{ {8}^{2} } + \sqrt{ {6}^{2} } \\ = \sqrt{100} \\ = 10cm$

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