Question

Area of the right angled triangle ABC right angled at B and AB = 3cn , BC =

4 cm

and AC = 5 cm, is

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Answer 1

Answer:

Area of ∆ ABC = (1/2)(AB)(BC)

Area of ∆ ABC = (1/2)(AB)(BC)= (1/2)(3)(4) = 6 cm^2 …….(1)

Area of ∆ ABC = (1/2)(AB)(BC)= (1/2)(3)(4) = 6 cm^2 …….(1)If the hypotenuse is taken as the base and BD as the height then the area of the ∆ABC

Area of ∆ ABC = (1/2)(AB)(BC)= (1/2)(3)(4) = 6 cm^2 …….(1)If the hypotenuse is taken as the base and BD as the height then the area of the ∆ABC= (1/2)(AC)(BD)

Area of ∆ ABC = (1/2)(AB)(BC)= (1/2)(3)(4) = 6 cm^2 …….(1)If the hypotenuse is taken as the base and BD as the height then the area of the ∆ABC= (1/2)(AC)(BD)=> (1/2)(5)(BD) = 6 from (1)

Area of ∆ ABC = (1/2)(AB)(BC)= (1/2)(3)(4) = 6 cm^2 …….(1)If the hypotenuse is taken as the base and BD as the height then the area of the ∆ABC= (1/2)(AC)(BD)=> (1/2)(5)(BD) = 6 from (1)=> BD = 12/5 = 2.4 cm.

Answer 2

Answer:

length of AC is 5cm

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