Area of the right triangle enclosed by the line passing through the points (-1,6) and (0,5)
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Step-by-step explanation:
Correct option is
A
9 sq.unit
Given Points are (0,0),(6,0),(4,3)
comparing with (x
1
,y
1
),(x
2
,y
2
),(x
3
,y
3
)
∴ Area of triangle =
2
1
∣x
1
(y
2
−y
3
)+x
2
(y
3
−y
1
)+x
3
(y
1
−y
2
)∣
=
2
1
∣0(0−3)+6(3−0)+4(0−0)∣
=
2
1
∣0+18+0∣=9
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