Area of the second Brillouin zone in a two dimensional square lattice of lattice constant a is
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Explanation:
For the planes that make up the first Brillouin zone boundary, the distance from ⃗Ghkl2 G → h k l 2 to Γ is smaller than the distance from ⃗Ghkl2 G → h k l 2 to any of the other reciprocal lattice vectors. By computing these distances, the planes that make up the first Brillouin zoneboundary can be determined.
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