Math, asked by jamesthaokip77, 9 months ago

Area of the shaded region = Area of square PQRS - Area of AQPU – Area of AQRT
= (20 x 20) cm? - (20 x 10) cm? - (20 x 10) cm
= (400 - 100 - 100) cm
200 cm
Exercise 19.2
1. One side of a parallelogram is 1 m 20 cm. Its distance from the opposite side is 80 cm. Find the area
the parallelogram.
2. The difference in length between the two adjacent sides of a parallelogram is 5 cm. If the perimeter
the parallelogram is 58 cm, find measure of all its sides.
3. Measure of one side of a parallelogram is 12 cm. If its area is 204 cm”, find the distance of the give
side from its opposite side.
4. The base of a parallelogram is thrice its height. If its area is 675 cm”, find the measures of base and
height of the parallelogram.
One of the diagonals of a rhombus is 11.6 m. If area of the rhombus is 49.3 m², find the length of
other diagonal.
The area of a rhombus is 102 cm and its perimeter is 48 cm. Eind the distance of a side of the
thomibus from its opposite side
rectangular lawn is of length 20 m and breadth 10 m with triangular flower​

Answers

Answered by samruddhicbse28
1

pls next time crop only one or two questions

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