Question

Area of the trapezium is 80m2and its parallel sides are 1m and 2.2m, its perpendicular distance is​

Answer 1

Given :-

• Area of the trapezium is 80m² and its parallel sides are 1m and 2.2m.

To Find :-

• Perpendicular Height = ?

Solution :-

The area of a trapezium is calculated as :

• Area of trapezium = ½ × (a + b) × h

where h is the perpendicular height and a, b the parallel bases.

Here Area of trapezium = 80 m², h = ?, a = 1m and b = 2.2 m.

• According to Question :-

⋙ Area of trapezium = ½ × (a + b) × h

⋙ 80 m² = ½ × (1m + 2.2m) × h

⋙ 80 = ½ × 3.2 × h

⋙ 80 = 1.6h

⋙ h = 80 ÷ 1.6

⋙ h = 50 m

Therefore, Height of trapezium is 50 m.

Extra Shots :-

• Volume of cylinder = πr²h
• T.S.A of cylinder = 2πrh + 2πr²
• Volume of cone = ⅓ πr²h
• C.S.A of cone = πrl
• T.S.A of cone = πrl + πr²
• Volume of cuboid = l × b × h
• C.S.A of cuboid = 2(l + b)h
• T.S.A of cuboid = 2(lb + bh + lh)
• C.S.A of cube = 4a²
• T.S.A of cube = 6a²
• Volume of cube = a³
• Volume of sphere = 4/3πr³
• Surface area of sphere = 4πr²
• Volume of hemisphere = ⅔ πr³
• C.S.A of hemisphere = 2πr²
• T.S.A of hemisphere = 3πr²

Answer 2

Question :

To find perpendicular distance of a trapezium.

Solution :

Given :

• Area of trapezium = 80 m²
• Parallel sides :
• a = 1 m
• b = 2.2 m

Formula to find Area :

${\boxed{\bf{\underline{Area \: of \: Trapezium \: = \frac{1}{2} \times (a + b) \times h }}}}$

• a and b parallel sides of trapezium

• h is the perpendicular distance or height of trapezium.

So, Area of trapezium is 80 m² ,

Parallel sides are 1 m and 2.2 m.

Then, to find perpendicular distance :

$\sf \longrightarrow \: \frac{1}{2} (a + b) \times h \: = 80 \: {m}^{2} \\ \\ \longrightarrow\sf \: \frac{1}{2} \times (1 + 2.2 )\times h = 80 \\ \\ \longrightarrow\sf \: \frac{1}{2} \times 3.2 \times h = 80 \\ \\ \sf\longrightarrow \: 1.6 \: h \: = 80 \\ \\ \sf\longrightarrow \: h \: = \frac{80}{1.6} \\ \\ \bf \: h = 50$

so , Perpendicular height = 50 m

Let's verify :

$= > \sf \: \frac{1}{2} \times (a + b) \times h \: = 80 \: {m}^{2}$

$= > \sf \: \frac{1}{2} \times (1 + 2.2) \times 50 = 80$

$= > \sf \: \frac{1}{2} \times 3.2 \times 50 = 80$

$= > \sf \: 1.6 \times 50 = 80$

$= > \sf \: 80 = 80$

$\bf \: LHS \: = \: RHS \:$

Thus solved !!