Question

Area of the trapezium is 80m2and its parallel sides are 1m and 2.2m, its perpendicular distance is​

Answer 1

Given :-

• Area of the trapezium is 80m² and its parallel sides are 1m and 2.2m.

To find :-

• Perpendicular distance.

Solution :-

• Area of trapezium = 80cm²

• Length of parallel sides = 1m and 2.2 m

As we know that

→ Area of trapezium = ½ (a + b) × h

Where " (a + b) " is sum of parallel sides and " h " is Altitude.

• According to the question

→ Area of trapezium = 80m²

→ ½ (a + b) × h = 80

→ ½ (1 + 2.2) × h = 80

→ ½ × 3.2 × h = 80

→ 1.6 × h = 80

→ h = 80/1.6

→ h = 50 m

Therefore,

• Height of trapezium is 50m

More to know :-

• Area of circle = πr²

• Circumference of circle = 2πr

• Perimeter of rectangle =2(l + b)

• Perimeter of square = 4 × side

• Area of square = side × side

• Area of rhombus = ½ × product of diagonals

• Area of Parallelogram = base × height

Answer 2

Answer:

✯ Given :-

• Area of the trapezium is 80 m² and its parallel sides are 1 m and 2.2 m.

✯ To Find :-

• What is the perpendicular distance of the trapezium.

✯ Formula Used :-

✫ Area Of Trapezium = $\dfrac{1}{2}$(a + b) × h ✫

✯ Solution :-

⋆ Given :-

• Area = 80 m²
• Parallel sides = 1m and 2.2 m

➣ According to the question by using the formula we get,

⇒ $\dfrac{1}{2}$(1 + 2.2) × h = 80

⇒ $\dfrac{1}{2}$ × 3.2 × h = 80

⇒ 1.6 × h = 80

⇒ h = $\sf\dfrac{\cancel{80}}{\cancel{1.6}}$

➠ h = 50

$\therefore$ The perpendicular distance of the trapezium is 50 m.

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