Question

area of the trapezium shaped field is480m the distance between two parrelel sides is 15m and one of the parrelel side is 20m find the other parrelel side.​

Answer 1

Answer:

Step-by-step explanation:

Area of a trapezium A is given by

A = 1/2 (a + b) h

If one side is a, the other side is 'a-16' since the difference of the parallel sides is 16

⇒ 1/2 (a + a - 16) x 15 = 300

1/2 (2a - 16) x 15 = 300 Multiply both sides by 2

(2a - 16)x15 = 600 Divide both sides by 15

2a - 16 = 40

2a = 56

a = 28

28 - 16 = 12

∴ The sides are 28 m and 12 m

Answer 2

Question:-

area of the trapezium shaped field is480m² the distance between two parrelel sides is 15m and one of the parrelel side is 20m find the other parrelel side.

Answer:-

• The length of another parallel side is 44 m.

To find:-

• Length of another parallel side

Solution:-

• Area of trapezium = 480 m²
• One parallel side (a) = 20 m
• Height of trapezium = 15 m

As we know,

$\large{ \boxed{ \mathfrak{area = \frac{a + b}{2} \times h}}}$

Where,

• a and b = parallel sides
• h = height of trapezium

Let,

• Second parallel side = x

According to question,

$\large{ \tt : \implies \: \: \: \: \: \: \: \: \frac{20 + x}{2} \times 15 = 480}$

$\large{ \tt : \implies \: \: \: \: \: \: \: \: (20 + x) \times 15 = 480 \times 2}$

$\large{ \tt : \implies \: \: \: \: \: \: \: \: 20 + x = \frac{480 \times 2}{15} }$

$\large{ \tt : \implies \: \: \: \: \: \: \: \: 20 + x = 64}$

$\large{ \tt : \implies \: \: \: \: \: \: \: \: x = 64 - 20}$

$\large{ \tt : \implies \: \: \: \: \: \: \: \: x = 44}$

Hence,

• The length of another parallel side is 44 m.