Question

area of the triangle ADC=?
Area of the triangle BDC=?
Ratio of areas of these triangles=?
Ratio in which CD divides AB=?​

Answer 1

Answer:

Let ABC is a ∆ whose base is AB . D is a point on AB such that AB=5cm and

DB=3cm. Thus AD=AB-DB= 5–3 =2cm.

Join C to D . draw a perpendicular CP on AB .

Area of ∆ ADC/Area of ∆ABC. = 1/2×CP×AD/1/2×CP×AB.

=AD/AB

=2cm/5cm

=2/5. or. 2 : 5. Answer

Step-by-step explanation:

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Answer 2

Answer:

your answer is 2/5. or 2:5.