Question

Area of the triangle formed by A(6, 0), B(7, 6) and C(3, 3) such that the length of the perpendicular from the point A to BC is 4.2 units, is​

Answer 1

Answer:

10.5 units

Step-by-step explanation:

hope this helps :)

Answer 2

Answer:

10.5 sq. units

Step-by-step explanation:

if there are two coordinates p,q then you can find the distance between them is,

$\sqrt{ {( px - qx)}^{2} + {( py - qy )}^{2} }$

therefore,

$BC = \sqrt{ {( 7 - 3 )}^{2} + {( 6 - 3 )}^{2} } \\ = \sqrt{16 +9 } = \sqrt{25} = 5$

As perpendicular from BC to A that is height of triangle that is 4.2 units.

therefore,

$area = \frac{1}{2} \times BC \times 4.2 \\ = \frac{1}{2} \times 5 \times 4.2 = 10.5$

therefore area is 10.5 sq. units.