Math, asked by yashrathore8924, 9 months ago

Area of the triangle formed by the coordinate axes and thine passing through the points (3,4) and (5,6) is

Answers

Answered by Kunalag14
1

Answer:0.5

Step-by-step explanation

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Answered by umiko28
4

Step-by-step explanation:

let A=(3,4)B(5,6)C(0,0)

area ABC=1/2(X1[Y2-Y3) +X2(y3-y1) +X3(y1-y2)]

ABC=1/2[3(6-0)+5(0-4)+0(4-0)]

=1/2[18-20+0]

=1/2×-2

=-1

=1unit

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