Area of the
triangle having vertices
(x,y) , (x, y) and (x3,y3)
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Answer:-
Let the first point be A(x1,y1),
The second be B(x2,y2),
And the third be C(x3,y3).
So the area of triangle so formed is equal to-
1/2 |x1(y2–y3) + x2(y3-y1) + x3(y1-y2)|
-×-×-×-×-×-
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Hope it helps! ^ _ ^
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