Question

Area of ​​the triangle whose perimeter is 22cm , one side 10cm and the difference of the other two sides is 6cm is​

Answer 1

Answer:

Hence the area of given triangle is 13.26 sq.cm

Answer 2

Answer:

$\sqrt55 cm^{2}$

Step-by-step explanation:

perimeter = 22cm

side a = 10cm

side b = 12cm

side c = 6cm (because 12-6 is 6cm and the difference is 6cm)

semi perimeter (s) = $\frac{a+b+c}{2}$

s = $\frac{22}{2}$ = 11cm

Area using Heron's formula = $\sqrt{s(s-a)(s-b)(s-c)}$

$\sqrt{11(11-10)(11-12)(11-6)cm^{2} } \\\\\sqrt{11 . 1 . 1 . 5cm^{2} }\\\\\sqrt{55 cm^{2} }$