Math, asked by alparaval158, 1 day ago

Area of the triangle whose vertices are (3,4),(4,5)and (2,-3)

a) 1 sq. unit
b) 5 sq. unit
c) 3 sq. unit
d) 2 sq. unit​

Answers

Answered by Anonymous
7

Given: Coordinates of a triangle are (3, 4), (4, 5) and (2, -3)

To find: The area of the triangle formed by the given coordinates.

Solution:

Whenever we are given three coordinates of a triangle and we are asked to find the area of this triangle, we may use the following formula:

  •  \boxed{ \sf Area = \dfrac12 \bigg| x_1(y_2 - y_3) +x _2(y_3 - y_1) + x_3(y_1 - y_2)\bigg| }

Let the given coordinates be:

  • (x1, y1) = (3, 4)
  • (x2, y2) = (4, 5)
  • (x3, y3) = (2, -3)

Therefore the area is given by:

 { \sf\implies Area = \dfrac12 \bigg| x_1(y_2 - y_3) +x _2(y_3 - y_1) + x_3(y_1 - y_2)\bigg| }

{ \sf\implies Area = \dfrac12 \bigg| 3(5 - ( - 3)) +4( - 3 - 4) + 2(4 - 5)\bigg| }

{ \sf\implies Area = \dfrac12 \bigg| 3(8) +4( -7) + 2( - 1)\bigg| }

{ \sf\implies Area = \dfrac12 \bigg| 24  - 28  - 2\bigg| }

{ \sf\implies Area = \dfrac12 \bigg| - 6\bigg| }

{ \sf\implies Area = \dfrac12(6)}

  \purple{\boxed{ \sf\implies Area = 3}}

Therefore the area of triangle is 3 sq. units.

Option (C) is correct.

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