Area of the triangle whose vertices are D(-1/2,5/2), E(7,3), F(7/2,7/2)
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Step-by-step explanation:
if midpoint of any triangle are given then area of triangle is 4 times area of triangle form by joining midpoints of triangle
now use above concept
first find ar (DEF)=1/2 {(-1/2)(3-7/2)+7(7/2-5/2)+7/2(5/2-3)}
=1/2 (1/4+7-7/4)
=11/4 square unit
now
area of ABC=4x11/4=11 square unit.
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