Question

Area of the triangle with vertices P(0,6). Q(0.2) and R(2, 0) is
A. 4 square unit
B.O
C. 8 square unit
D. 6 square unit.​

Answer 1

Answer:

8 sq unit

Step-by-step explanation:

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Answer 2

Given:-

• Vertices of a ∆PQR are
• P(0,6) $\mapsto \: {(x_1,y_2)}$
• Q(0,2) $\mapsto \; {(x_2,y_2)}$
• R(2,0) $\mapsto \; {(x_3,y_3)}$

To Find:-

• Area of the ∆PQR.

Solution:-

$\boxed{\bold{Area\;of\; Triangle = \frac{1}{2}|x_1(y_2-y_3)\;+\;x_2(y_3-y_1)\;+\;x_3(y_1-y_2)|}}$

$\frac{1}{2} |0(2 - 0) + 0(0 - 6) + 2(6 - 2)| \\ \frac{1}{2} |0(2) + 0( - 6) + 2(4)| \\ \frac{1}{2} |0 + 0 + 8| \\ \frac{1}{2} |8| \\ \frac{1}{\cancel{2}}±{\cancel{8}} \\±4$

As, The Area is Not in Negative.

Area of ∆PQR is $\longmapsto\;\Large\sf{4\:sq.units}$

• Option A.

☞ To Remove Modules We Had Taken ±.

$\bold{@MrMonarque}$

Hope It Helps You ✌️