area of trapezium 3m& its altitude is 27 find sum of the lengths of its parallel sides
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area of trapezium= 0.5(a+b)h
3= 0.5(a+b)27
a+b= 6/27
a+b= 2/9
3= 0.5(a+b)27
a+b= 6/27
a+b= 2/9
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area =1/2 ×(a+b)×h
3=1/2×(a+b)×27
6/27=a+b
a+b=2/9
a+b=0.22m
3=1/2×(a+b)×27
6/27=a+b
a+b=2/9
a+b=0.22m
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