Question

area of trapezium is 1586sq m its hight is 26 m and one of the parallel sides is 84m find the other

Answer 1

Let Given Trapezium be ABCD such that AB parallel to CD.
  We are given AB=84m, and height=26m

 We know that ar(trap.)= 1/2(Sum of parallel sides)(height)
                                  1586  = 1/2(84+CD)(26)
                                   1586 = 13(84+CD)
                                   so, 84+CD = 1586/13
                                   so, 84+CD = 122
                                             so, CD= 122-84 = 38 m
      
                  so, the other side is 38 m

             Hope this helps Plz mark as brainliest

Answer 2

$area \: \: of \: trapezium = \frac{1}{2} (a + b) \times h \\ 1586 = \frac{1}{2} \times 26 \times (84 + b) \\ \frac{1586 \times 2}{26} = 84 + b \\ b + 84 = 122 \\ b = 38 \: m {}^{2}$
second side =38 m

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