Question

area of trapezium is 45 square cm and the height is 6 cm find the length of the two parallel side in one side is twice the other​

Answer 1

${\blue{Hola!!}}$

Given:-

Area of trapezium=45 cm²
Height (h)=6 cm

let the parallel sides be x and the other parallel side be 2x

Area of trapezium:-
${\frac{1}{2}}$×(sum of parallel sides)×Height

45= ${\frac{1}{2}×}$(x+2x)6

${\frac{45}{6}}$=${\frac{1}{2}×}$(3x)

7.5=${\frac{1}{2}×}$(3x)

7.5×2=3x

15=3x

x=${\frac{15}{3}}$

x=5 cm

So the parallel sides will be

x=5 cm

and

2x=2×5=10 cm

Answer 2

Step-by-step explanation:

let one side be x another be 2x

define area of trapezium equals to half into base into height