Question

area of trapezium is 56cm^2 and height is 4 cm find the length of the two parallel. one side is 4cm greater than the other

Answer 1

Answer: Two parallel sides are 12cm and 16cm

Step-by-step explanation: Given below in the picture...

Answer 2

Answer:

12 cm & 16 cm for the smaller

& bigger sides respectively

Step-by-step explanation:

TAKE the trapezium as ABCD.......

ar(ABCD)=56cm^2;

Let AB be x

then, CD=x+4 cm;

Area of trapezium=

$(a + b) \div 2 \times h$

thus,

56 cm^2=(x+x+4cm)/2*4cm

56 cm^2=(x+x+4cm)*2cm

56 cm^2=4x cm + 8cm^2

4x cm= 48 cm^2

x = (48 cm^2)/4 cm= 12 cm

Also,,

CD= x+ 4cm= 16cm