area of trapezium when side one is 7 cm and side two is 11 cm and height is 6 CM
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Answered by
1
Answer:
area of the trapezium =(a+b)×h/2
here a=7 cm
b=11 cm
h=6 cm
so, area =(7+11)×6/2 sq cm=54 sq cm
Answered by
9
Answer:
In Trapezium
- Length of one side = 7 cm
- Length of second side = 11 cm
- Height of Trapezium = 6 cm
Area of Trapezium = 1/2 x sum of parallel sides x height
Area of Trapezium = 1/2 x ( 7 + 11 ) x 6
- 1/2 x 18 x 6
- 1/2 x 108
- 54 cm²
Hence, Area of trapezium is 54 cm²
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