Math, asked by abdullaharselan, 2 months ago

area of trapezium when side one is 7 cm and side two is 11 cm and height is 6 CM

Answers

Answered by bagkakali
1

Answer:

area of the trapezium =(a+b)×h/2

here a=7 cm

b=11 cm

h=6 cm

so, area =(7+11)×6/2 sq cm=54 sq cm

Answered by studylover001
9

Answer:

In Trapezium

  • Length of one side = 7 cm
  • Length of second side = 11 cm
  • Height of Trapezium = 6 cm

Area of Trapezium = 1/2 x sum of parallel sides x height

Area of Trapezium = 1/2 x ( 7 + 11 ) x 6

  • 1/2 x 18 x 6
  • 1/2 x 108
  • 54 cm²

Hence, Area of trapezium is 54 cm²

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