Math, asked by punit1372, 8 months ago

area of trapezium with parallel sides of length 10 cm and 12 cm and height 5.5 cm is​

Answers

Answered by yellowflower221206
2

Answer:

60.5cm^2

Step-by-step explanation:

10+12=22

22/2=11

11*5.5=60.5

Answered by zahaansajid
2

Area =

 \frac{1}{2} h(a + b) \\  =  \frac{1 \times 5.5(10 + 12)}{2}  =  \frac{5.5 \times 22}{2}  \\  = 60.5cm {}^{2}

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