area of trapezium with parallel sides of length 8 cm and 10 cm and height 6.5 cm
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Answered by
2
AnSwer -:
The area of trapezium-: 52 cm^2
_______________________________
_______________________________
Area of trapezium-;
“A = 1/2 x h x (a +b)”
A = Area
H = height
(A +b ) = sum of parallel sides
_______________________________
Explanation-:
Given ,
H = height = 6.5 cm
Length of parallel sides are -: 6 cm and
10 cm
To find,
Area of trapezium
______________________________
Then
Area of trapezium-;
“A = 1/2 x h x (a +b)”
A = Area
H = height = 6.5 cm
(A +b ) = sum of parallel sides = (6+10)
Now ,
1/2 x 6.5 x(6+10)
1/2 x 6.5 x 16
6.5 x 8
= 52 cm^2
Hence ,
The area of trapezium-: 52 cm^2
_______________________________
Trapezium-: A trapezium is a flat shape
with four straight sides, one pair of
opposite sides being parallel and the
other pair not parallel.
_______________________________
The area of trapezium-: 52 cm^2
_______________________________
_______________________________
Area of trapezium-;
“A = 1/2 x h x (a +b)”
A = Area
H = height
(A +b ) = sum of parallel sides
_______________________________
Explanation-:
Given ,
H = height = 6.5 cm
Length of parallel sides are -: 6 cm and
10 cm
To find,
Area of trapezium
______________________________
Then
Area of trapezium-;
“A = 1/2 x h x (a +b)”
A = Area
H = height = 6.5 cm
(A +b ) = sum of parallel sides = (6+10)
Now ,
1/2 x 6.5 x(6+10)
1/2 x 6.5 x 16
6.5 x 8
= 52 cm^2
Hence ,
The area of trapezium-: 52 cm^2
_______________________________
Trapezium-: A trapezium is a flat shape
with four straight sides, one pair of
opposite sides being parallel and the
other pair not parallel.
_______________________________
Answered by
1
Answer:
A=a+b/2 h
8+10/2 × 6.5
= 58.5
Step-by-step explanation:
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