Question

area of triangle=104 square cm,base of triangle =13square cm ,find its altitude​

Answer 1

Answer: 16

Area of trinagle = 104

Base of triangle = 13

Altitude or Height = ?

Area of triangle = 1/2 x Base x altitude

104 = 1/2 x 13 x altitude

104 x 2 = 13 x altitude

208 = 13 x altitude

altitude x 13 = 208

altitude = 208/13

Altitude = 16

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Answer 2

Given :

• Area If the triangle = 104 cm²
• Base of the triangle = 13 cm²
• Altitude of the triangle = ??

To Find :

• Altitude of the triangle ?

Formula To Be Applied:

We will use the formula of area of the triangle:

• Area = ½×base×hight

Concept:

We are given with the area of the triangle and its hieght and we need to find the Altitude (hieght) of the triangle.

As with the formula of area if triangle Given above, we can change the formula as :

• Height = 2Area/Base

So, we will use this formula to calculate the hieght .

Solution :

Given, Area = 104 cm²

Base = 13cm²

So, using the formula stated Above :

$\displaystyle \rm \implies hieght = \frac{2 \: area}{base}$

$\implies \displaystyle \rm hieght = \frac{2 \times 104}{13}$

$\implies \displaystyle \rm hieght = \frac{208}{13}$

$\implies \displaystyle \rm hieght = \frac{ \cancel{208}}{ \cancel{013}}$

$\red{ \underline{ \boxed{ \implies \displaystyle \rm hieght = 16 \: cm}}}$

Hence, The hieght of triangle = 16 cm

Final Answer :

The Hieght of the triangle = 16 cm

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Additional Information:

Some Formulas related to mensuration:

•Area of triangle = ½×base×hieght

$\displaystyle \rm \bull \: area \: of \: \triangle = \sqrt{s(s - a)(s - b)(s - c)}$

•Perimeter of triangle = a+b+c

•Perimeter of square = 4×side

•Area of square = side²

•Volume of cube = side³

•TSA of cube = 6×side²

•Perimeter of rectangle = 2(l+b)

•Area of rectangle = l×b

•Volume of cuboid = l×b×h

•TSA of cuboid = 2(lb+bh+lh)

•Area of circle = pi(r²)

•Perimeter of circle = 2(pi)r

•Volume of Sphere = 4/3(pi)r³

•Volume pf Cylinder = pi(r²)h