Question

Area of triangle ABD is 10square cm and area of trinagle ADC is 12sq.cm
(a) Find BD:DC
(b) If BD=5cm,find DC​

Answer 1

Answer:

According to the theorem of area of similar triangles

BD²÷ DC²= 10÷12

BD : DC= √5÷6

Given: the value of BD= 5cm

The value of DC= √(5÷6)×5

Answer 2

Answer:  

The value of DC is 6 cm.

Solution:

According to the question,

Given Data:

Area of triangle ABD is 10 square cm and area of triangle ADC is 12 sq.cm

To Find:

(a) Find BD: DC

(b) If BD=5cm,

Step-by-step Explanation:

Step 1:

Area of triangle ADB $=h \times \frac{b_{1}}{2}$

10 $=h \times \frac{5}{2}$

To find the value of h:

Step 2:

h=4 cm

The value of h is 4 cm

Area of ADC $=h \times \frac{b_{2}}{2}$

Step 3:      

12= $4 \times \frac{b_{2}}{2}$

Step 4:

\frac{C D}{b_{2}}=\frac{24}{4}=6 \mathrm{cm}

BD: DC=5:6

Step 5:

Result:

The value of DC is 6 cm.