Area of triangle formed by x/3+y/2=1 then coordinate axis with. squnits.
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Area of triangle is given by 1/2 * 2 * 3. = 3
where 3 and 2 are x and y intercepts respectively.
where 3 and 2 are x and y intercepts respectively.
Answered by
3
Hi ,
x/3 + y/2 = 1 [ intercepts form ]
x -intercept = a = 3
y - intercept = b = 2
Required area of the ∆ = 1/2| ab |
= 1/2 | 3 × 2 |
= 6/2
= 3 square units
I hope this helps you.
: )
x/3 + y/2 = 1 [ intercepts form ]
x -intercept = a = 3
y - intercept = b = 2
Required area of the ∆ = 1/2| ab |
= 1/2 | 3 × 2 |
= 6/2
= 3 square units
I hope this helps you.
: )
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