Question

Area of triangle if sides are 3cm, 3cm and 3cm.​

Answer 1

Step-by-step explanation:

$area \: of \: tri = \binom{1}{2} \times base \times height$

=1/2×3×3

=1/2×6

=3

area of triangle is 3sq.cm

Answer 2

Answer:

$\dfrac{9\sqrt{3}}{4} \txt{cm}^2$

Step-by-step explanation:

There are a few formulae to find area of the a triangle:

1. Area = 1/2 x base x height

  {You will need the perpendicular height to use this formula)

2. Area = 1/2 ab sin C

  (You need 2 sides and the angle in-between to use this formula)

3. Area = √s(s - a)(s - b) (s - c)

  (You need to know the length of all the 3 sides)

So in this case, we could apply the 3rd formula to find the area.

However, since the triangle here is an equilateral triangle (All sides are equal)

We can also use the specific formula for equilateral triangle:

$\txt {Area = }\dfrac{\sqrt{3}}{4}s^2$

Find the area where side = 3 cm:

$\txt {Area = }\dfrac{\sqrt{3}}{4}(3)^2$

$\txt {Area = }\dfrac{\sqrt{3}}{4}(3)^2 = \dfrac{9\sqrt{3}}{4} \txt{cm}^2$