Area of triangle is 110 degrees and one of the interior opposite angles is 30° find the other two angles of the triangle
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area of triangle = 110°
one intr. opp. angle = 30°
and 1st angle angles = x
x+30°=110°
x= 110°-30°
x=80°
2nd angle=y
x+y+30°=180°
80°+y+30°=180°
110°+y=180°
y=180°-110°
y=70°
one intr. opp. angle = 30°
and 1st angle angles = x
x+30°=110°
x= 110°-30°
x=80°
2nd angle=y
x+y+30°=180°
80°+y+30°=180°
110°+y=180°
y=180°-110°
y=70°
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