area of triangle is 360 cm if it base is 15cm long find correspondingly altitudes
Answers
Step-by-step explanation:
ar. of = 1/2 × base × height
A/C
360= 1/2 ×15 × h
48= h
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Given:-
- Area of triangle is 360 cm².
- Base of triangle is 15 cm.
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To Find:-
- Altitude of a triangle.
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Solution:-
Here,
- Area = 360 cm²
- Base = 15 cm
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According to the question
★Formula used:-
Area of triangle = ½ × Base × Height
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→ 360 = ½ × 15 × h
→ 360 = 7.5 × h
→ h = 360/7.5
→ h = 48 cm
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Hence,
- Altitude of a triangle is 48 cm.
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More Formulas:-
→ Area of rectangle = length × breadth sq.units
→ Perimeter of square = 4 × side units
→ Area of square = side × side sq.units
→ Perimeter of circle = 2πr units
→ Area of circle = πr² sq.units
→ Perimeter of parallelogram = 2 × (a + b) units
→ Area of parallelogram = base × height sq.units
→ Perimeter of rhombus = 4 × side units
→ Area of rhombus = 1/2 × diagonal (1) × diagonal (2) sq.units
→ Perimeter of equilateral triangle = 3 × side units
→ Area of equilateral triangle = √3/4 × a² = 1/2 × side × height sq.units
→ Perimeter of trapezoid = (Sum of all sides) units
→ Area of trapezoid = 1/2 × height × (sum of parallel sides) sq.units