Question

area of triangle whose side are 4cm, 6cm, 8cm​

Answer 1

Answer:

$3 \sqrt{15} \: {cm}^{2}$

Step-by-step explanation:

Sides :-

a = 4 cm

b =6 cm

c = 8 cm

$s = \frac{perimeter}{2} \\ = ) \frac{4 + 6 + 8}{2} \\ = ) \frac{18}{2} \\ = )9$

BY HERON'S FORMULA :-

$\sqrt{s(s - a)(s - b)(s - c)} \\ = ) \sqrt{9(9 - 4)(9 - 6)(9 - 8)} \\ = ) \sqrt{9 \times 5 \times 3 \times 1} \\ = )3 \sqrt{5 \times 3} \\ = )3 \sqrt{15 } \: {cm}^{2}$

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