Area of Triangle whose side is 55,44,33
Answers
Answer:
Step-by-step explanation:
The area of a triangle of sides 33, 44 and 55 cm is 726 cm² (Heron's formula), but if we calculate the height corresponding to the side measuring 44 cm, it comes out to be 33 cm. These results violate the Pythagorean theorem. How can this be possible?
Answer:
Given: A triangle who’s sides are 33 cm, 44 cm, and 55 cm and has an area of 726 sq cm.
By looking at the side numbers (33,44, and 55), it appears that we have a 3–4–5 right triangle.
let base(b) = 33 and height(h) = 44
Area(A) = (1/2)(b)(h)
A = (1/2)(33)(44)
A = 726 sq cm>>>> ck good
Pythagorean theorem: hypotenuse(c) = base2+height2−−−−−−−−−−−−−√
c = 332+442−−−−−−−−√
c = 3025−−−−√
c = 55 cm>>>> ck good
I don’t see the problem, Pythagorean theorem is not being violated formula for finding area works.
Answer:
Semi Perimeter:a+b+c/2
Area of triangle:√s(s-a) (s-b) (s-c)
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