Question

area of triangle whose sides are 40m 32m 24m

Answer 1

a = 40 m

b = 32 m

c = 24 m

S = ( a + b + c) / 2

=> S = ( 40 + 32 + 24) / 2

=> S = 96 / 2

=> S = 48

(S-a) = 48 - 40 = 8

(S-b) = 48 - 32 = 16

(S-c) = 48 - 24 = 24


$area \: = \sqrt{s(s - a)(s - b)(s - c)} \\ \\ = \sqrt{48 \times 8 \times 16 \times 24} \\ \\ = \sqrt{24 \times 2 \times 8 \times 8 \times 2 \times 24} \\ \\ = 24 \times 2 \times 8 \\ \\ = 48 \times 8 \\ \\ = 384 \: {m}^{2}$

Answer 2

a= 40m
b= 32m
c= 24m

s= ( a+b+c )/2
= (40+32+24)/2
=96/2
=48


so, the area of the triangle is √s(s-a)(s-b)(s-c)
=√48(48-40)(48-32)(48-24) m²
=√48×8×16×24 m²
=√2×2×2×2×3×2×2×2×2×2×2×2×2×2×2×3 m²
= 2×2×2×2×2×2×2×3 m²
= 384 m²


hope it helps you...... please mark as brainliest ☺☺☺☺