Question

Area of triangle whose sides are150cm,120cm,200cm

Answer 1

Solution:
Use Heron's Formula;
First find S = (A+B+C)/2 = (150+120+200)/2
= 235

& Area = √[S(S-A) (S-B) (S-C)]
Area = √[235(235-150) (235-120) (235-200)]
= √[235 x 85 x 115 x 35]
= √80399375
= 8966.569 cm^2

Answer is Area of the given triangle is 8966.569 cm^2.

Answer 2

$\huge{\underline{\underline{\red{♡Solution→}}}}$

__________________________

$\bold{\huge{\underline{\underline{\rm{ Given :}}}}}$

Sides,

a = 150

b = 120

c = 200

$\bold{\huge{\underline{\underline{\rm{ To\:Find :}}}}}$

Area of Triangle .

__________________________

The herons formula to find Area of Triangle is :

$area(a) = \sqrt{p(p - a)(p - b)(p - c)}$

Where P is half perimeter.

$p = \frac{a + b + c}{2}$

__________________________

$\purple{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

First find out the value of P.

$p = \frac{150+120+200}{2} \\ p = \frac{470}{2}$

$p = 235$

Now Area is ,

$a = \sqrt{235(235 - 150)(235-120)(235-200)} \\ a = \sqrt{235 \times 85 \times 115 \times 35}$

$a = \sqrt{80399375}$

$\boxed{a =8,966.56986 }$

__________________________

───── ❝ TheEnforceR ❞ ─────

Mark as Brainliest !! ✨✨