Question

Area of triangle whose sides r 4 3 and 6

Answer 1

Sides
a= 4cm
b= 3cm
c= 5cm
S= a+b+c/2
= 4+3+5/2
= 12/2
= 6
(s-a)= 6-4=2
(s-b)=6-3= 3
(s-c)= 6-5=1

by applying herons formula
Area of a triangle = √s(s-a)(s-b)(s-c)
= √ 6*2*3*1
=√2*3*2*3( 6= 2*3)
= 2 * 3 ( 2*2*3*3)
=6cm²

Answer 2

Hello friend!
Here's ur answer!
P= 4cm
Q= 3cm
R= 5cm
S= p+q+r /2
= 4+3+5/2
= 12/2
= 6
(s- p)= 6-4=2
(sq)=6-3= 3
(s-r )= 6-5=1
Area of a triangle = √s(s- p)(s- q)(s- r)
= root (6*2*3*1)
=root 6(2*3*2*3)
= root 2* 3 ( 2*2*3*3)
=6cm²