Question

Area of triangle whose vertices (4,2),(1,3)and(2,3)is
A)0.5
B)1.5
C)3.5
D)4.5

Answer 1

Answer:

We know that the area of the triangle whose vertices are (x

1

,y

1

),(x

2

,y

2

), and (x

3

,y

3

) is

2

1

∣x

1

(y

2

−y

3

)+x

2

(y

3

−y

1

)+x

3

(y

1

−y

2

)∣

The given vertices of the triangle are A(−3,−1),B(5,3) and C(2,−8)

Area of the triangle =

2

∣−3(3−(−8))+5(−8−(−1))+2(−1−3)∣

=

2

∣−33−35−8∣

=

2

∣−76∣

=

2

76

=38 square units.

hope this will help you.