Math, asked by omjadhavoj70, 4 months ago

Area of triangle whose vertices are A(0.0) , B(3,1) , c(2,4) is

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Answered by hashimumme501

0

Answer:

A triangle with squared sides A , B , and C has an area a that satisfies: 16a2=4AB−(C−A−B)2. Here we have. A=22+32=13. B=22+52=29. C=32+52=34.

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