Question

Area of triangle whose vertices are A(5,8), B(5,0),C(1,0)

Answer 1

Answer:

${\pink{\green{\sf{\therefore Area\:of\:triangle=16\:units}}}}$

Step-by-step explanation:

$\huge{\pink{\green{\underline{\red{\sf{SOLUTION-}}}}}}$

• In the given question information given about a traingle whose vertices are given in coordinate system.

• We have to find the area of triangle.

$\underline \bold{Given :} \\ \implies ABC\: is \: a \: triangle \: in \: which \\ \implies A = (5,8) \\ \implies B = (5,0) \\ \implies C= (1,0) \\ \\ \underline \bold{To \: Find : } \\ \implies Area \: of \: triangle = ?$

• According to given question :

• We know the formula of area of triangle for coordinate system.

$\implies Area \: of \: triangle = \frac{1}{2}( x_{1}( y_{2} - y_{3}) + x_{2}(y_{3} - y_{1}) + x_{3}(y_{1} - y_{2})) \\ \implies Area = \frac{1}{2}(5(0 - 0) + 5(0 - 8) + 1(8 - 0) \\ \implies Area = \frac{1}{2} (0 - 40 + 8) \\ \implies Area = \frac{1}{2}( - 32) \\ \implies Area = - 16 \: units \\ \bold{ \implies Neglect \: negative \: sign : } \\ \bold{ \therefore Area = 16 \: units}$

• We negelect negative sign because area can't be in negative. The area comes negative because area is located on coordinate system.

Answer 2

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