area of two similar triangles trianglePQR is 50cm2 and triangleXYZ is 72cm2 PQ=5 then find XY
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ar(PQR)/ar (XYZ)=PQ^2/XY^2
=50/72=25/XY^2
=XY^2=25×72/50
=XY=6
THEOREM=the ratio of areas of two similar triangles is equal to the ratio of square of their corresponding sides
=50/72=25/XY^2
=XY^2=25×72/50
=XY=6
THEOREM=the ratio of areas of two similar triangles is equal to the ratio of square of their corresponding sides
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