Question

Area rombus 72 and perimeter 82 find attitude

Answer 1

Answer:



Step-by-step explanation: Using the formulas

A=pq

2

P=4a

a=p2+q2

2

There are 2 solutions forp

p=2P2P2+P4﹣256A2﹣2P4﹣256A2P2+P4﹣256A2

64A=2·822·822+824﹣256·722﹣2·824﹣256·722·822+824﹣256·722

64·72≈3.52525

p=2P2P2﹣P4﹣256A2+2P4﹣256A2P2﹣P4﹣256A2

64A=2·822·822﹣824﹣256·722+2·824﹣256·722·822﹣824﹣256·722

64·72≈40.84817

Answer 2

apply rhombus formula
1 by 2. 72 multiply 82
72divide 2. =36
36 multiply 82
2352