Question

area under a curve |x|+|y|=2​

Answer 1

Answer:

Step-by-step explanation:

the curve is a square

vertices are   A [2,0], B [0,2] , C[-2, 0 ] ,  D [0, -2 ]

SIDE  = a = AB = $\sqrt{[2-0]^{2}+[0-2]^{2}  } =\sqrt{4+4} =\sqrt{8}$

area   = a^2 = 8