Area under curve find the area of a triangle whose vertices are a(1,-2) b(3,5) c(5,2)
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Here is ur answer it will be 10sq. units
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Step-by-step explanation:
we have to use the formula 1/2(x1(y2-y3)+x2(y3-y1)+x3(y1-y2)
1/2{(1(5-2)+3(2+2)+5(-2-5)}
1/2{(1(3)+3(4)+5(-7)}
1/2{(3+12-35)}
1/2{(15-35)}
1/2(-20)
= - 10
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