Question

Area under curve y=x2 from x=0 to x=3 with x-axis​

Answer 1

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Area under curve y=x2 from x=0 to x=3 with x-axis

Now,

$area = \displaystyle \int _ 0^3 \: y \: \: dx \\ = \int _ 0^3 \: {x}^{2} \: \: dx \\ = [ \frac{ {x}^{3} }{3} ] _ 0^3 \\ = \frac{1}{3} ( {3}^{3} - {0}^{3} ) \\ = \frac{27}{3} \\ = 9 \: {unit}^{2}$