Question

Area under the curve y = sin2x + cos2x between x = 0 and x = π/4 is.

(A) 2 Sq. units

(B) 1 Sq. units

(C) 3 Sq. units

(D) 4 Sq. units​

Answer 1

Answer:-

$Required \: answer \: ∫ {}^{\pi/4}o \: \\ (sin2x + cos2x) dx$

$= [ - \frac{cos2x}{2} + \frac{sin2x}{2} ] {}^{\pi/4} o$

$= \frac{1}{2} [ - cos \frac{\pi}{2} + sin \: \frac{\pi}{2} + cos \: 0 -sin \: 0 ] \\ \\ = 1sq.units$

$Option \: (B) \: is \: the \: correct \: answer.$

Step-by-step explanation:

@ANSWERER

Answer 2

Answer:-

$Required \: area = \\ \: \: ∫ {}^{\pi/4} o(sin2x + cos2x)dx$

$= [ - \frac{cos2x}{2} + \frac{sin2x}{2} ] {}^{π/4} o$

$= \frac{1}{2} [ - cos \frac{\pi}{2} + sin \: \frac{\pi}{2} + cos \: 0 - sin \: 0 \\ \\ = 1sq.unit$

$∴ Option \: (B) \: is \: the \: correct \: answer ✅$