Area under the curve y=v3x + 4 between x=0 and x=4 is
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Step-by-step explanation:
m=3x+4
dm=3dx
When x=0 , m=4 ,
x=4 , m=16
∫043x+4dx
=31∫416mdm
=31[23m23]416
92[43−23]=92×56squnits
=9112squnits
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SIMILAR QUESTIONS
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