Question

areas of two similar triangles are 225 sq cm and 80 sq cm. if a side if the bigger triangle is 20cm then find the corresponding side of the smaller triangle​

Answer 1

Answer:

56.25 cm

Step-by-step explanation:

First we have to find the ratio of area

225:80

= 45:16

$\frac{45}{16}$

Let x be the length of smaller triangle

45/16=20/x

then, x= (45×20)/16

x= 900/16

x= 56.25 cm

please Mark me Brainliest

Then I will follow you

Answer 2

Step-by-step explanation:

let triangles are ∆abc and ∆pqr

area of ∆abc=225sq cm And area of ∆pqr =80sq cm

then given side is 20cm and let other corresponding side is x cm।।

now, we know that if two triangles are similar then ratio of square of corresponding side is equal to area ratio then

20x20/x^2 = 225/80

400/x^2 = 225/80

x^2= 400 x 80/225

x^2 = 32000/225

x^2 = 141(approx)

then,

x= √141

x= 21 cm