Question

areas of two similar triangles are 225 sq.cm.and 81 sq.cm .if a side of the smaller triangle is 12 CM find corresponding side of bigger triangle???​

Answer 1

Answer:

20 cm

Step-by-step explanation:

side of smaller triangle = 12 s1

area of smaller triangle = 81  a1

area of larger triangle = 225  a2

as the triangle are similar

the ratio of the square of the side = area of the triangles

(s1$)^{2}$:(s2$)^{2}$  = 81:225

s2$)^{2}$ = (144*225)/81

s2$)^{2}$=400

s2=20 cm

side of the larger triangle is 20 cm ANSWER

Answer 2

Answer:

20cm

Step-by-step explanation:

Let  the similar triangles be ABC and PQR respectively and  QR = 12cm

Therefore, we have to find BC

Ratio of areas of similar triangle = Square of ratios of their side

  $\frac{Area( ABC )}{Area( PQR )} = (\frac{AB}{PQ} )^{2}$

= $\frac{225 }{81} = (\frac{AB}{PQ} )^{2}$

= $\frac{15}{9} = \frac{AB}{PQ}$

= $\frac{5}{3} = \frac{AB}{PQ}$

Since, Triangles are similar, $\frac{AB}{PQ} = \frac{BC}{QR} = \frac{AC}{PR}$

  $\frac{5}{3} = \frac{BC}{12}$

= 12 × 5 = 3BC

= 60 = 3BC

= $\frac{60}{3}$ = BC

= 20cm = BC