Question

areas of two similar triangles are 27 centimetre square and 80 centimetres square one side of the bigger triangle is 4 root 5 centimetre then find the corresponding side of the smaller Triangle

Answer 1

let bigger triangle=ABC, and smaller =PQR
SO....ar(PQR)/ar(ABC)=(side of PQR)^2/(side of ABC)^2
which equals to..
27/80=(x/4root5)^2
27×80/80=x
x=27