Question

Areas of two similar triangles are 338 sq cm and 200 sq cm.
Find the ratio of the corresponding sides.​

Answer 1

$\large \underline{ \underline{ \sf \: Solution :</p><p> \: \: \: }}$

Given ,

$\star$Area of 1st triangle (T1) = 338 cm²

$\star$Area of 2nd triangle (T2) =200 cm²

It is known that ,

The ratios of the areas of two similar triangles is equal to the square of their corresponding sides

So ,

$\fbox{ \fbox{\sf \: \frac{ \: area \: of \: T_{1} \: }{ \: area \: of \: T_{2} \: } = { \: \: ( \frac{ \: \: \: side \: of \:T_{1} \: \: \: }{ \: \: side \: of \:T_{2}} )}^{2} }}$

$\implies \sf \frac{338}{200} = { \: \: ( \frac{ \: \: \: \: side \: of \:T_{1} \: \: \: \: }{ \: \: side \: of \:T_{2}} )}^{2} \\ \\ \sf \: Taking \: square \: root \: on \: both \: side \: \\ \\ \implies \sf \sqrt{\frac{338}{200} } = \sqrt{{ \: \: ( \frac{ \: \: \: \: side \: of \:T_{1} \: \: \: \: }{ \: \: side \: of \:T_{2}} )}^{2} } \\ \\\implies \sf \frac{ \sqrt{338} }{ \sqrt{200} } = \frac{ \: \: \: \: side \: of \:T_{1} \: \: \: \: }{\: \: side \: of \:T_{2}} \\ \\\implies \sf \frac{ \: \: \: \: side \: of \:T_{1} \: \: \: \: }{\: \: side \: of \:T_{2}} = \frac{18.38 }{14.14}$

$\therefore$The ratio of the corresponding sides. are 18.38 : 14.14 or 14.14 : 18.38

Answer 2

Answer:

ratio of the side of triangle = 13:10

Step-by-step explanation: